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NTSE Sample Paper NTSE SAT Practice Test-6

  • question_answer
    In the given figure, BA is parallel to CD, \[\angle DAC=\angle ABC\] but \[\ne \,{{90}^{\text{o}}}\], AB = 10 cm,  BC = 9 cm and AC = 15 cm. The length of AD in cm is                      

    A) 11.5                 

    B) 11.0

    C) 13.0                 

    D)        13.5      

    Correct Answer: D

    Solution :

    [d] \[\Delta ACB\sim \Delta CDA\] \[\therefore \frac{AB}{CA}=\frac{BC}{AD}\] \[\Rightarrow \frac{10}{15}=\frac{9}{AD}\,\,\,or\,\,AD=13.5\,cm\]


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