A) 40 km/h
B) 48 km/h
C) 50 km/h
D) none of these
Correct Answer: B
Solution :
[b] Total distance = S Total time taken = \[=\frac{{}^{S}/{}_{2}}{40}+\frac{{}^{S}/{}_{2}}{60}\] \[=\frac{5S}{240}\] \[=\frac{S}{48}\] \[\therefore \,\,Average\text{ }speed\frac{Total\,\,Dis\tan ce}{Total\text{ }time}\] \[=\frac{S}{{}^{S}/{}_{48}}\] =48km/h
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