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NTSE Sample Paper NTSE SAT Practice Test-20

  • question_answer
    If x% of y=1% of z; y% of z=1 of x and z% of x=1% of y,  then the value of the expression \[(xy+yz+zx)\] is equal to

    A) 1                                 

    B) 2

    C) 3            

    D) 4                 

    Correct Answer: C

    Solution :

    [c] x % of y = 1 % of z \[\Rightarrow \] xy = z. Similarly, yz = x and xz = y. This is true only if \[x=y=z=1\] \[\therefore \,\,\,xy+yz+zx=3\]                


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