A) 1
B) \[\frac{1}{2}\]
C) \[\frac{1}{4}\]
D) 2
Correct Answer: B
Solution :
[b] \[\sqrt{248+\sqrt{51+13}}\div 32\] \[=\text{ }\sqrt{248+8}\div 32\] \[=\text{ }\sqrt{256}\div 32=16\div 32=\text{ }\frac{1}{2}\]You need to login to perform this action.
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