NTSE Sample Paper NTSE SAT Practice Test-19

  • question_answer
    If three cubes having edges 0.3 m; 0.4 m and 0.5 m respectively are melted and formed into a single cube, then what is surface of this cube?

    A) \[1.08{{m}^{2}}\]                   

    B) \[1.56{{m}^{2}}\]

    C) \[1.84{{m}^{2}}\]                   

    D) \[2.16{{m}^{2}}\]

    Correct Answer: D

    Solution :

    [d] Volume of the new cube \[={{\left( 0.3 \right)}^{3}}+{{\left( 0.4 \right)}^{3}}+{{\left( 0.5 \right)}^{3}}\] \[=0.216\,\,{{m}^{3}}={{(0.6)}^{3}}\] \[\therefore \] edge of cube = 0.6 m Surface area \[=6\text{ }{{\left( 0.6 \right)}^{2}}\text{ }{{m}^{2}}\text{ }=\text{ }2.16\text{ }{{m}^{2}}.\]


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