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NTSE Sample Paper NTSE SAT Practice Test-19

  • question_answer
    When \[{{x}^{40}}+2\]is divided \[{{x}^{4}}+1\] remainder?                        

    A) 1                                 

    B) 2          

    C) 3          

    D) 4          

    Correct Answer: C

    Solution :

    [c] \[{{x}^{4}}+1=0\Rightarrow {{x}^{4}}=-1.\] Remainder \[={{\left( {{x}^{4}} \right)}^{10}}+2={{\left( -1 \right)}^{10}}+2=1+2=3.\]                   


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