A) 56:69:99
B) 56:99:69
C) 69:56:99
D) 99:56:69
Correct Answer: B
Solution :
[b] Income of A, B and C \[=7x,\text{ }9x\,\,\,and\text{ }12x~\] ...(i) Expenses of A, B and C \[=8y,\,\,9y\,\,\,and\text{ }15y\] ...(ii) Savings of A, B and C \[=7x-8y;\text{ }9\left( x-y \right);\text{ }3\left( 4x-5y \right)\] ?(iii) Now\[7x-8y=\frac{1}{4}\] of \[7x\Rightarrow 21x\text{ =}\,32y\] or \[\frac{x}{32}=\frac{y}{21}\] \[\therefore \,\,x=32\,\,K,y=21\,K\] Substituting in (iii), we have savings as 56: 99: 69. [Short cut: Clearly B has 9 parts in his income as well as in expenditure ratio. Obviously his savings also be a multiple of 9. So only in [b] such a condition is satisfied].
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