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NTSE Sample Paper NTSE SAT Practice Test-17

  • question_answer
    If \[\frac{37}{13}=2+\frac{1}{x+\frac{1}{y+\frac{1}{z}}}\] where x, y, z are natural numbers, then x, y, z are respectively

    A) 1, 2, 5

    B) 1, 5, 2

    C) 5, 2, 11

    D) 11, 2, 5

    Correct Answer: B

    Solution :

    [b] \[\frac{37}{13}=2\frac{11}{13}=2+\frac{1}{\frac{13}{11}}\] \[=2+\frac{1}{1+\frac{2}{11}}=2+\frac{1}{1+\frac{1}{\frac{11}{2}}}=2+\frac{1}{1+\frac{1}{5+\frac{1}{2}}}\] \[\therefore \text{ }x=1,\text{ }y=5\text{ }and\text{ }z=2\]


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