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NTSE Sample Paper NTSE SAT Practice Test-16

  • question_answer
    In a triangle ABC, the bisectors of angles B and C meet at M. Then ZBMC is equal to

    A) \[90{}^\circ \]                          

    B) \[90{}^\circ +ZA\]

    C) \[90{}^\circ +\frac{1}{2}\angle A\] 

    D)        \[90{}^\circ -\frac{1}{2}\angle A\]

    Correct Answer: C

    Solution :

    Not Available  


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