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NTSE Sample Paper NTSE SAT Practice Test-11

  • question_answer
    If \[a+b+c=0\],tei1faevalueof\[\frac{{{a}^{2}}}{bc}+\frac{{{b}^{2}}}{ca}+\frac{{{c}^{2}}}{ab}\]is

    A) -3                                

    B) 0

    C) 1                                 

    D) 3

    Correct Answer: D

    Solution :

    [d] General expression \[=\frac{{{a}^{3}}+{{b}^{3}}+{{c}^{3}}}{abc}=\frac{3abc}{abc}=3.\]


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