A) \[24c{{m}^{2}}\]
B) \[27\sqrt{3}c{{m}^{2}}\]
C) \[12\,c{{m}^{2}}\]
D) \[12\sqrt{3}\,c{{m}^{2}}\]
Correct Answer: B
Solution :
[b] In an equilateral triangle, centroid and circumcentre coincide, therefore, Circumradius (R) \[=\frac{a}{\sqrt{3}}=6\] \[\therefore \,\,\,a=6\sqrt{3}\,\,\,cm\] Area \[=\frac{\sqrt{3}}{4}\times {{a}^{2}}\] \[=\frac{\sqrt{3}}{4}\times {{(6\sqrt{3})}^{2}}\] \[=\frac{\sqrt{3}}{4}\times 36\times 3\] \[=27\sqrt{3}\,\,c{{m}^{2}}\]
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