NTSE Sample Paper NTSE SAT Practice Test-10

  • question_answer
    How many real values of x satisfy the equation\[{{x}^{\frac{2}{3}}}+{{x}^{\frac{1}{3}}}-2=0?\]

    A) Only 1 value     

    B) 2 values

    C) 3 values            

    D)        No value

    Correct Answer: B

    Solution :

    [b] \[{{x}^{1/3}}=y\] \[\therefore \text{ }{{y}^{2}}+y-2=0\] \[\left( y+2 \right)\left( y-1 \right)=0,\]which gives \[y=1,-2\] or x = 1 or \[x\text{ }=-\text{ }8\]are the solutions, hence 2 values


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