NEET Sample Paper NEET Sample Test Paper-9

  • question_answer \[N{{a}_{2}}C{{O}_{3}}\] cannot be used in place of \[{{(N{{H}_{4}})}_{2}}C{{O}_{3}}\] for the identification of \[C{{a}^{2+}},B{{a}^{2+}}\] and \[S{{r}^{2+}}\] ions because

    A)  Concentration of \[CO_{3}^{2-}\] ions is very low

    B)  \[N{{a}^{+}}\] ions will interfere with the detection of \[C{{a}^{2+}},B{{a}^{2+}}\] and \[S{{r}^{2+}}\]

    C)  Sodium will react with acid radicals.

    D)  Magnesium will be precipitated.

    Correct Answer: D

    Solution :

    \[N{{a}_{2}}C{{O}_{3}}\] is completely dissociated to \[N{{a}^{+}}\] and \[CO_{3}^{2-}\] ions thus giving high concentration of \[CO_{3}^{2-}\] ions which would precipitate \[M{{g}^{2+}}\] as \[MgC{{O}_{3}}\].


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