NEET Sample Paper NEET Sample Test Paper-9

  • question_answer If potassium chlorate is 80% pure, then 48 g of oxygen would be produced from (atomic mass of K=39)

    A)  \[153.12g\] of \[KCl{{O}_{3}}\]

    B)  \[122.5\text{ }g\] of \[KCl{{O}_{3}}\]

    C)  \[245\,g\] of \[KCl{{O}_{3}}\]    

    D)  \[98\text{ }g\] of \[KCl{{O}_{3}}\]

    Correct Answer: A

    Solution :

    \[\begin{matrix}    2KCl{{O}_{3}}  \\    2(39+35.5+48)  \\    =245\,g  \\ \end{matrix}\,\,\,\,\,\,\begin{matrix}    \xrightarrow{{}}  \\    {}  \\    {}  \\ \end{matrix}\,\,\,\,\,\,\begin{matrix}    2KCl+3{{O}_{2}}  \\    3\times 32  \\    =96g  \\ \end{matrix}\] \[48\,\,g\] \[{{O}_{2}}\] will be produced from \[KCl{{O}_{3}}\]                                 \[=\frac{245}{96}\times 48=122.5\,g\] \[80%\] pure \[KCl{{O}_{3}}\]required             \[=\frac{100}{80}\times 122.5\]                 \[=153.12\,g\]


You need to login to perform this action.
You will be redirected in 3 sec spinner