• # question_answer A Vernier caliper has 20 divisions on the Vernier scale which coincide with 39 on the main scale. The latest count of the instrument is $0.1mm$. The main scale divisions are of: A)  $0.5\,mm$                      B)  $1\,mm$C)  $2\,mm$                         D)  ${\scriptstyle{}^{1}/{}_{4}}\,mm$

If value of one division of main scale is X, then Least count $=\frac{X}{Total\text{ }number\text{ }of\text{ }division}$ $\therefore$  $X=0.1\times 20=2mm$