• # question_answer If resistance of each wire in the network shown, is r. The equivalent resistance between A and C is equal to: A)  $r$                                      B)  $\frac{r}{2}$C)                  $\frac{2r}{3}$                                D)  $\frac{3r}{2}$

For points A and C, loop BCD is short circuited Hence$,$        ${{R}_{AC}}=\frac{r\times 2r}{3r}=\frac{2}{3}r$.