NEET Sample Paper NEET Sample Test Paper-9

  • question_answer A wire \[l=8\,m\]long of uniform cross-sectional area \[A=88{{m}^{2}},\] has a conductance of \[G=2.45{{\Omega }^{-2}}\]. The resistivity of material of the wire will be:

    A)  \[2.1\times {{10}^{-7}}\Omega -m\]

    B)  \[3.1\times {{10}^{-2}}\Omega -m\]

    C)  \[4.1\times {{10}^{-7}}\Omega -m\]   

    D)  \[5.1\times {{10}^{-7}}\Omega -m\]

    Correct Answer: C

    Solution :

    As, the resistivity, \[\rho =\frac{RA}{l}=\frac{A}{Gl}\] \[=\frac{8\times {{10}^{-6}}}{2.45\times 8}=4.1\times {{10}^{-7}}\Omega m.\]


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