A) \[\frac{g}{3}\]
B) \[\frac{5g}{7}\]
C) \[\frac{2g}{3}\]
D) \[\frac{5g}{14}\]
Correct Answer: D
Solution :
As the popular formula for acceleration of the rolling bodies on an inclined plane, is \[a=\frac{g\,\sin \theta }{\left( 1+\frac{1}{m{{R}^{2}}} \right)}=\frac{g\sin {{30}^{o}}}{\left( 1+\frac{2}{5} \right)}=\frac{5}{14}g\]You need to login to perform this action.
You will be redirected in
3 sec