• question_answer A position dependent force, $F={{X}^{2}}-3N,$ acts on a small body mass, 2 kg and displaces it from $X=0$to $X=5m$ the work done is: A)  $110\,J$                    B)  $\frac{80}{3}\,J$C)  $\frac{95}{3}\,J$                 D)  zero

As we know that, $w=\int_{{{x}_{1}}}^{{{x}_{2}}}{F\,dx}$ $=\int_{0}^{5}{({{x}^{2}}-3)dx=\left[ \frac{{{x}^{3}}}{3}-3x \right]}_{0}^{5}$ $=\frac{125}{3}-15=\frac{80}{3}J$