A) \[{1}/{24\,{{\min }^{-1}}}\;\]
B) \[\frac{0.692}{24}\,{{\min }^{-1}}\]
C) \[\frac{2.303}{24}\,\log \,\left( \frac{1}{8} \right)\,{{\min }^{-1}}\]
D) \[\frac{2.303}{24}\,\log \,\left( \frac{8}{1} \right)\,{{\min }^{-1}}\]
Correct Answer: D
Solution :
[d]\[k=\frac{2.303}{t}\log \frac{a}{a-x}\]\[=\frac{2.303}{24}\log \frac{1}{\frac{1}{8}}=\frac{2.303}{24}\log \frac{8}{1}{{\min }^{-1}}\]
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