A) \[\underline{N}{{O}_{2}}\] and \[{{\underline{N}}_{2}}{{O}_{4}}\]
B) \[{{\underline{P}}_{2}}{{O}_{5}}\] and \[{{\underline{P}}_{4}}{{O}_{10}}\]
C) \[{{\underline{N}}_{2}}O\] and \[\underline{N}O\]
D) \[\underline{S}{{O}_{2}}\] and \[\underline{S}{{O}_{3}}\]
Correct Answer: D
Solution :
[d] O.N. of N in \[N{{O}_{2}}\]and \[{{N}_{2}}{{O}_{4}}\] is\[+4\] \[\therefore \] difference is zero. O.N. of P in \[{{P}_{2}}{{O}_{5}}\] and \[{{P}_{4}}{{O}_{10}}\] is\[+5\] \[\therefore \] difference is zero O.N. of N in \[{{N}_{2}}O\]is \[+1\] and in NO is\[+2.\] The difference is 1 O.N. of S in \[S{{O}_{2}}\] is \[+4\] and in \[S{{O}_{3}}\] is \[+6.\] The difference is \[+2.\]
You need to login to perform this action.
You will be redirected in
3 sec
