A) \[{{C}_{6}}{{H}_{5}}CHO+C{{H}_{3}}N{{O}_{2}}\]\[\xrightarrow{KOH}{{C}_{6}}{{H}_{5}}CHCHN{{O}_{2}}\]
B) \[{{C}_{6}}{{H}_{5}}CHO+{{(C{{H}_{3}}CO)}_{2}}O\]\[\xrightarrow{C{{H}_{3}}COONa}{{C}_{6}}{{H}_{5}}CH=CHCOOH\]
C) \[{{C}_{6}}{{H}_{5}}CHO+C{{H}_{3}}CHO\]\[\xrightarrow{NaOH}{{C}_{6}}{{H}_{5}}CH=CHCHO\]
D) \[{{C}_{6}}{{H}_{5}}CHO+C{{H}_{2}}{{(COOH)}_{2}}\]\[\xrightarrow{Alc.N{{H}_{3}}}{{C}_{6}}{{H}_{5}}CH=CHC{{O}_{2}}H\]
Correct Answer: B
Solution :
[b] In general, \[Ph=\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-H+C{{H}_{3}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-O-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\xrightarrow{{}}\] \[\underset{Cinnamic\,\,acidAcetic\,\,acid}{\mathop{Ph-CH=CH-COOH+C{{H}_{3}}COOH}}\,\]
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