A) \[\underset{(4-methyl-1-pentanal)}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}-C{{H}_{2}}-CHO}}\,\]
B) \[\underset{\text{(4}-\,\text{methyl}\,\,-\text{2}-\,\text{pentyn}\,\,-\text{1}-\,\text{oic}\,\,\text{acid)}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C\equiv C-COOH}}\,\]
C) \[\underset{\text{(2}-\text{methyl}\,\,-1\,-\,\text{pentanoic}\,\,\text{acid)}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}\underset{\underset{C{{H}_{3}}}{\mathop{|}}\,}{\mathop{-\,CH-}}\,COOH}}\,\]
D) \[\underset{(3-\,\,\text{hexen}\,-5-\,\,\text{one})}{\mathop{C{{H}_{3}}-C{{H}_{2}}-CH=CH-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\]
Correct Answer: D
Solution :
[d] \[\underset{(hex-3-ene-2-one)}{\mathop{\overset{6}{\mathop{C}}\,{{H}_{3}}\overset{5}{\mathop{C}}\,{{H}_{2}}\overset{4}{\mathop{C}}\,H=\overset{3}{\mathop{C}}\,H\overset{O}{\mathop{^{2}\overset{||}{\mathop{C}}\,}}\,\overset{1}{\mathop{C}}\,{{H}_{3}}}}\,\]
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