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NEET Sample Paper NEET Sample Test Paper-91

  • question_answer
    Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is:

    A) 1.00 M 

    B)         2.00 M

    C) 2.50 M 

    D)        4.00 M

    Correct Answer: B

    Solution :

    [b]  Given mass of solute \[(w)=120\,g\] mass of solvent \[(w)=1000\,g\] Mol. mass of solute \[=60\,g\] density of solution \[=1.12\,g/mL\] From the given data, Mass of solution \[=1000+120=1120\,g\] \[\because \]\[d=\frac{\text{Mol}\text{. mass}}{\text{V}}\] or \[V=\frac{\text{Mol}\text{. mass}}{\text{d}}\] Volume of solution \[V=\frac{1120}{1.12}=1000\,mL\] or = 1 litre Now molarity\[(M)=\frac{\text{W}}{\text{Mol}\text{.mass }\!\!\times\!\!\text{ V(lit}\text{.)}}\] \[=\frac{120}{60\times 1}=2M\]


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