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NEET Sample Paper NEET Sample Test Paper-91

  • question_answer
    A body is projected at an angle of \[30{}^\circ \] to the horizontal with speed 30 m/s. What is the angle with the horizontal after 1.5 seconds? Take \[g=10m/{{s}^{2}}.\]

    A) \[0{}^\circ \]    

    B)                    \[30{}^\circ \]

    C) \[60{}^\circ \]              

    D)        \[90{}^\circ \]

    Correct Answer: A

    Solution :

    [a] \[{{u}_{x}}=30\cos 30{}^\circ =30\sqrt{3}/2,,\] \[{{u}_{y}}=30\sin 30{}^\circ ,\] \[{{v}_{y}}=30\sin 30{}^\circ -gt\] \[{{v}_{y}}=30\sin 30{}^\circ -10\times 1.5=0\] As vertical velocity = 0, Angle with horizontal \[\alpha =0{}^\circ \] It is a state, when a particle reach to a highest point of its path.


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