A) \[2.2\times {{10}^{6}}\]newton
B) 16 newton
C) 8 newton
D) 44 newton
Correct Answer: D
Solution :
[d] \[F=YA\,\alpha \,t\] \[=(2.0\times {{10}^{11}})({{10}^{-6}})(1.1\times {{10}^{-5}})(20)\] \[=44\,\,newton\]You need to login to perform this action.
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