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NEET Sample Paper NEET Sample Test Paper-91

  • question_answer
    A particle of mass \[{{m}_{1}}\] is moving with a velocity \[{{v}_{1}}\] and another particle of mass \[{{m}_{2}}\] is moving with a velocity \[{{v}_{2}}.\] Both of them have the same momentum but different kinetic energies are \[{{E}_{1}}\] And \[{{E}_{2}}\] respectively. If \[{{m}_{1}}>{{m}_{2}}\] then

    A) \[{{E}_{1}}={{E}_{2}}\]        

    B)        \[{{E}_{1}}<{{E}_{2}}\]

    C) \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{m}_{1}}}{{{m}_{2}}}\]        

    D)        \[{{E}_{1}}>{{E}_{2}}\]

    Correct Answer: B

    Solution :

    [b]  E\[=\frac{{{p}^{2}}}{2m}\] or,\[{{E}_{1}}=\frac{p_{1}^{2}}{2{{m}_{1}}},\]\[{{E}_{2}}=\frac{p_{2}^{2}}{2{{m}_{2}}}\] or,\[{{m}_{1}}=\frac{p_{1}^{2}}{2{{E}_{1}}},\]\[{{m}_{2}}=\frac{p_{2}^{2}}{2{{E}_{2}}}\] \[{{m}_{1}}>{{m}_{2}}\]\[\Rightarrow \]\[\frac{{{m}_{1}}}{{{m}_{2}}}>1\] \[\therefore \]\[\frac{p_{1}^{2}{{E}_{2}}}{{{E}_{1}}p_{2}^{2}}>1\]\[\Rightarrow \]\[\frac{{{E}_{2}}}{{{E}_{1}}}>l\,\,\,\,[\because {{p}_{1}}={{p}_{2}}]\] or, \[{{E}_{2}}>{{E}_{1}}\]


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