A) \[1.73\times {{10}^{-4}}M{{\min }^{-1}}\]
B) \[3.47\times {{10}^{-4}}M{{\min }^{-1}}\]
C) \[3.47\times {{10}^{-5}}M{{\min }^{-1}}\]
D) \[7.5\times {{10}^{-4}}M{{\min }^{-1}}\]
Correct Answer: D
Solution :
[d] For a first order reaction, we have \[k=\frac{2.303}{t}\log \frac{{{N}_{0}}}{N}\] \[\therefore \] \[k=\frac{2.303}{40\,\,\min }\log \frac{0.1}{0.005}\] \[=\frac{2.303}{40\,\,\min }\times \log \,20=\frac{2.303}{40}\times 1.3010\] Now rate = k \[\times \] [reactant] When [x]= 0.01 M \[\therefore \] rate \[=\frac{2.303}{40}\times 1.3010\times 0.01\,\,M\,{{\min }^{-1}}\] \[=7.5\times {{10}^{-4}}M\,\,{{\min }^{-1}}.\]
You need to login to perform this action.
You will be redirected in
3 sec
