A) \[{{f}_{1}}-{{f}_{2}}=\frac{{{\omega }_{1}}{{\omega }_{2}}}{2}{{f}_{2}}\]
B) \[{{\omega }_{1}}{{f}_{1}}+{{\omega }_{2}}{{f}_{2}}=0\]
C) \[\frac{{{\omega }_{1}}}{{{f}_{1}}}+\frac{{{\omega }_{2}}}{{{f}_{2}}}=0\]
D) \[\frac{{{f}_{1}}}{{{f}_{2}}}+\frac{{{\omega }_{1}}}{{{\omega }_{1}}}=0\]
Correct Answer: C
Solution :
[c] The condition for an achromatic doublet is \[\frac{{{\omega }_{1}}}{{{f}_{1}}}+\frac{{{\omega }_{2}}}{{{f}_{2}}}=0\] This gives the combination of two lenses which will be free from chromatic aberration.
You need to login to perform this action.
You will be redirected in
3 sec
