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NEET Sample Paper NEET Sample Test Paper-90

  • question_answer
    In \[{{S}_{N}}2\] reactions, the correct order of reactivity for the following compounds: \[C{{H}_{3}}Cl,\]\[C{{H}_{3}}C{{H}_{2}}Cl,\]\[{{(C{{H}_{3}})}_{2}}CHCl\] and \[{{(C{{H}_{3}})}_{3}}CCl\] is:

    A) \[C{{H}_{3}}Cl>{{(C{{H}_{3}})}_{2}}CHCl>C{{H}_{3}}C{{H}_{2}}Cl>{{(C{{H}_{3}})}_{3}}CCl\]

    B) \[C{{H}_{3}}Cl>C{{H}_{3}}C{{H}_{2}}Cl>{{(C{{H}_{3}})}_{2}}CHCl>{{(C{{H}_{3}})}_{3}}CCl\]

    C) \[C{{H}_{3}}C{{H}_{2}}Cl>C{{H}_{3}}Cl>{{(C{{H}_{3}})}_{2}}CHCl>{{(C{{H}_{3}})}_{3}}CCl\]

    D)  \[{{(C{{H}_{3}})}_{2}}CHCl>C{{H}_{3}}C{{H}_{2}}Cl>C{{H}_{3}}Cl>{{(C{{H}_{3}})}_{3}}CCl\]

    Correct Answer: B

    Solution :

    [b] Steric hindrance around the carbon atom undergoing the inversion process will slow down the \[{{S}_{N}}2\] reaction, hence less hindrance faster will the reaction. So, the order is \[C{{H}_{3}}Cl>C{{H}_{3}}C{{H}_{2}}-Cl>{{(C{{H}_{3}})}_{2}}CH-Cl>{{(C{{H}_{3}})}_{3}}CCl\]


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