A) \[{{M}_{0}}\]
B) \[\sqrt{2}\,{{M}_{0}}\]
C) \[\sqrt{3}\,{{M}_{0}}\]
D) \[2\,{{M}_{0}}\]
Correct Answer: C
Solution :
[c] \[{{M}_{net}}=\sqrt{M_{0}^{2}+M_{0}^{2}+2M_{0}^{2}\cos 60{}^\circ }\] \[=\sqrt{3M_{0}^{2}}=\sqrt{3}{{M}_{0}}\]
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