A) \[23.4\,\,S\,\,c{{m}^{2}}\,mol{{e}^{-1}}\]
B) \[23.2\,\,S\,\,c{{m}^{2}}\,mol{{e}^{-1}}\]
C) \[46.45\,\,S\,\,c{{m}^{2}}\,mol{{e}^{-1}}\]
D) \[54.64\,\,S\,\,c{{m}^{2}}\,mol{{e}^{-1}}\]
Correct Answer: B
Solution :
[b] Here, R= 31.6 ohm \[\therefore \]\[C=\frac{1}{R}=\frac{1}{31.6}oh{{m}^{-1}}=0.0316\,oh{{m}^{-1}}\] Specific conductance = conductance \[\times \]cell constant \[=0.0316\,oh{{m}^{-1}}\times 0.367\,c{{m}^{-1}}\] \[=0.0116\,oh{{m}^{-1}}c{{m}^{-1}}\] Now, molar concentration = 0.5 M (given) \[=0.5\times {{10}^{-3}}mole\,c{{m}^{-3}}\] \[\therefore \] Molar conductance \[=\frac{K}{C}=\frac{0.0116}{0.5\times {{10}^{-3}}}\] \[=23.2\,S\,\,c{{m}^{2}}mo{{l}^{-1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
