A) \[6.023\times {{10}^{18}}\]
B) \[6.023\times {{10}^{20}}\]
C) \[2\times 6.023\times {{10}^{20}}\]
D) \[3.011\times {{10}^{20}}\]
Correct Answer: B
Solution :
[b] Two \[N{{a}^{+}}\] ions are replaced by one \[S{{r}^{2+}}\]ion to maintain electrical neutrality. Hence, number of vacancies = Number of \[S{{r}^{2+}}\] ions doped \[=1.0\times {{10}^{-3}}\times 6.02\times {{10}^{23}}=6.02\times {{10}^{20}}\]
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