A) \[6.0\mu F\]
B) \[4.0\mu F\]
C) \[2.0\mu F\]
D) \[3.0\mu F\]
Correct Answer: A
Solution :
[a] Rearranging the circuits, we get the following circuit. \[\therefore \] Equivalent capacitance between A and B, \[{{C}_{AB}}=\frac{4\times 4}{4+4}=2\mu F\] and equivalent capacitance between C and D, \[{{C}_{CD}}=\frac{8\times 8}{8+8}=4\mu F\] \[\therefore \] \[{{C}_{ab}}=2\mu F+4\mu F=6\mu F\]You need to login to perform this action.
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