A) \[1.5N/C\]
B) \[1.5\times {{10}^{-10}}N/C\]
C) \[3\,N/C\]
D) \[3\times {{10}^{-10}}N/C\]
Correct Answer: C
Solution :
[c] Field between two parallel sheet \[=\frac{\sigma }{{{\in }_{0}}}=\frac{26.4\times {{10}^{-12}}}{8.85\times {{10}^{-12}}}=3\,\,N/C\]You need to login to perform this action.
You will be redirected in
3 sec