A) 4 m/sec
B) 6.25 m/sec
C) 16 m/sec
D) 8 m/sec
Correct Answer: A
Solution :
[a] Since water does not fall down, therefore the velocity of revolution should be just sufficient to provide centripetal acceleration at the top of vertical circle. So, \[v=\sqrt{(gr)}=\sqrt{\{10\times (1.6)\}}=\sqrt{(16)}=4\,m/sec.\]You need to login to perform this action.
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