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NEET Sample Paper NEET Sample Test Paper-89

  • question_answer
    When \[C{{H}_{3}}Cl\] and \[AlC{{l}_{3}}\] are used in Friedel-Crafts reaction, the electrophile is

    A) \[C{{l}^{+}}\]            

    B)        \[AlC{{l}_{4}}^{-}\]

    C) \[C{{H}_{3}}^{+}\]

    D)        \[AlC{{l}_{2}}^{+}\]

    Correct Answer: C

    Solution :

    [c] \[C{{H}_{3}}Cl\underset{Electrophile}{\mathop{+AlC{{l}_{3}}}}\,\xrightarrow{{}}C{{H}_{3}}^{+}+AlC{{l}_{4}}^{-}\]


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