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NEET Sample Paper NEET Sample Test Paper-89

  • question_answer
    If \[{{K}_{1}}\] and \[{{K}_{2}}\] are respective equilibrium constants for the two reactions \[Xe{{F}_{6}}(g)+{{H}_{2}}O\,(g)XeO{{F}_{4}}(g)+2HF\,(g)\] \[Xe{{O}_{4}}(g)+Xe{{F}_{6}}\,(g)XeO{{F}_{4}}(g)+Xe{{O}_{3}}{{F}_{2}}\,(g)\] the equilibrium constant for the reaction \[Xe{{O}_{4}}(g)+2HF\,(g)Xe{{O}_{3}}{{F}_{2}}(g)+{{H}_{2}}O\,(g)\] will be

    A) \[\frac{{{K}_{1}}}{K_{2}^{2}}\]        

    B)                    \[{{K}_{1}}.{{K}_{2}}\]

    C) \[\frac{{{K}_{1}}}{{{K}_{2}}}\]                      

    D)        \[\frac{{{K}_{2}}}{{{K}_{1}}}\]

    Correct Answer: D

    Solution :

    [d] Reaction (II) and reverse of reaction (I) gives the desired reaction hence \[K={{K}_{2}}\times \frac{1}{{{K}_{1}}}=\frac{{{K}_{2}}}{{{K}_{1}}}.\]


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