NEET Sample Paper NEET Sample Test Paper-89

  • question_answer
    The fraction of total volume occupied by the atoms present in a simple cube is

    A) \[\frac{\pi }{3\sqrt{2}}\]

    B)        \[\frac{\pi }{4\sqrt{2}}\]

    C) \[\frac{\pi }{4}\]            

    D)        \[\frac{\pi }{6}\]

    Correct Answer: D

    Solution :

    [d] Number of atoms per unit cell = 1 Atoms touch each other along edges. Hence \[r=\frac{a}{2}\] ( r = radius of atom and a = edge length) Therefore % fraction \[=\frac{\frac{4}{3}\pi {{r}^{3}}}{{{(2r)}^{3}}}=\frac{\pi }{6}=0.52\]


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