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NEET Sample Paper NEET Sample Test Paper-89

  • question_answer
    On adding 0.1 M solution each of \[[A{{g}^{+}}],\]\[[B{{a}^{2+}}],\]\[[C{{a}^{2+}}]\] in a \[NaS{{O}_{4}}\] solution, species first precipitated is \[[\]\[{{K}_{sp}}\,\,BaS{{O}_{4}}={{10}^{-11}},\]\[{{K}_{sp}}\,\,CaS{{O}_{4}}={{10}^{-6}},\]\[{{K}_{sp}}A{{g}_{2}}S{{O}_{4}}={{10}^{-5}}]\]

    A) \[A{{g}_{2}}S{{O}_{4}}\]       

    B)        \[BaS{{O}_{4}}\]

    C) \[CaS{{O}_{4}}\]         

    D)        All of these

    Correct Answer: B

    Solution :

    [b] The species having minimum value of \[{{K}_{sp}}\] will get precipitated first of all because ionic product will exceed the solubility product of such a species. The \[{{K}_{sp}}\] value is minimum for \[BaS{{O}_{4}}({{10}^{-11}}),\] so, \[BaS{{O}_{4}}\] will get precipitated first of all.


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