2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-89

  • question_answer
    Solid \[Ba{{(N{{O}_{3}})}_{2}}\] is gradually dissolved in a \[1.0\times {{10}^{-4}}\,\,M\,\,N{{a}_{2}}C{{O}_{3}}\] solution. At which concentration of \[B{{a}^{2+}},\] precipitate of \[BaC{{O}_{3}}\] begins to form? \[({{K}_{sp}}\,for\,BaC{{O}_{3}}=5.1\times {{10}^{-9}})\]

    A) \[5.1\times {{10}^{-5}}M\]       

    B)        \[7.1\times {{10}^{-8}}M\]

    C) \[4.1\times {{10}^{-5}}M\]       

    D)        \[8.1\times {{10}^{-7}}M\]

    Correct Answer: A

    Solution :

    [a] Given \[N{{a}_{2}}C{{O}_{3}}=1.0\times {{10}^{-4}}M\] \[\therefore \] \[[CO_{3}^{2-}]=1.0\times {{10}^{-4}}M\] i.e.      \[s=1.0\times {{10}^{-4}}M\] At equilibrium \[[B{{a}^{2+}}][CO_{3}^{2-}]={{K}_{sp}}\] of \[BaC{{O}_{3}}\] \[[B{{a}^{2+}}]=\frac{{{K}_{sp}}}{CO_{3}^{2-}}=\frac{5.1\times {{10}^{-9}}}{1.0\times {{10}^{-4}}}\]\[=5.1\times {{10}^{-5}}M\]


You need to login to perform this action.
You will be redirected in 3 sec spinner