A) \[0.01\,M\,{{H}_{2}}S<0.01\,M\,{{H}_{2}}S{{O}_{4}}<0.01\,M\,NaCl<0.01\,M\,NaN{{O}_{2}}\]
B) \[0.01\,\,M\,\,NaCl<0.01M\,\,NaN{{O}_{2}}<0.01\,\,M\,{{H}_{2}}S<0.01M\,{{H}_{2}}S{{O}_{4}}\]
C) \[0.01\,\,M\,\,NaN{{O}_{2}}<0.01M\,\,NaCl<0.01\,\,M\,{{H}_{2}}S<0.01M\,{{H}_{2}}S{{O}_{4}}\]
D) \[0.01\,\,M\,\,{{H}_{2}}S<0.01M\,\,NaN{{O}_{2}}<0.01\,\,M\,NaCl<0.01M\,{{H}_{2}}S{{O}_{4}}\]
Correct Answer: C
Solution :
[c] \[{{H}_{2}}S{{O}_{4}}\] is a strong acid hence \[pH<7,\] or \[{{[H]}^{+}}>{{10}^{-7}},\] the aqueous solution of NaCI is neutral hence \[pH\approx 7\] or \[[{{H}^{+}}]\approx {{10}^{-7}}.\] The aqueous solution of \[NaN{{O}_{2}}\] will be basic hence\[pH>7\]or \[[{{H}^{+}}]<{{10}^{-7}}\] \[{{H}_{2}}S\] is a weak acid. Therefore, the correct order will be \[0.01\,\,M\,\,NaN{{O}_{2}}<0.01\,\,M\,\,NaCl<0.01\,\,M\,\,{{H}_{2}}S<0.01\,\,M\,\,{{H}_{2}}S{{O}_{4}}\]
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