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NEET Sample Paper NEET Sample Test Paper-89

  • question_answer
    A projectile is fired from the surface of the earth with a velocity of \[5\,\,m{{s}^{-1}}\] and angle \[\theta \] with the horizontal. Another projectile fired from another planet with a velocity of \[3\,\,m{{s}^{-1}}\] at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in \[m{{s}^{-2}}\]) given g \[=9.8\,\,m{{s}^{2}}\]

    A) 3.5       

    B)        5.9  

    C) 16.3                 

    D)        110.8

    Correct Answer: A

    Solution :

    [a] Horizontal range \[=\frac{{{u}^{2}}\sin \,2\theta }{g}\] so g \[\propto \] \[{{u}^{2}}\] or  \[\frac{{{g}_{planet}}}{{{g}_{earth}}}=\frac{{{({{u}_{planet}})}^{2}}}{{{({{u}_{earth}})}^{2}}}\] Therefore \[{{g}_{planet}}={{\left( \frac{3}{5} \right)}^{2}}(9.8\,\,m/{{s}^{2}})\] \[=3.5\,m/{{s}^{2}}\]


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