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NEET Sample Paper NEET Sample Test Paper-89

  • question_answer
    Three blocks of masses \[{{m}_{1}},\] \[{{m}_{2}}\] and \[{{m}_{3}}\] are connected by a massless strings, as shown, on a frictionless table. They are pulled with a force \[{{T}_{3}}=40\,N.\] If\[{{m}_{1}}=10kg,\]\[{{m}_{2}}=6kg\]and\[{{m}_{3}}=4\,kg,\] the tension \[{{T}_{2}}\] will be

    A) 20 N                            

    B) 40 N

    C) 10 N                

    D)        32 N

    Correct Answer: D

    Solution :

    [d] For equilibrium of all 3 masses, \[{{T}_{3}}=({{m}_{1}}+{{m}_{2}}+{{m}_{3}})\]a or \[a=\frac{{{T}_{3}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\] For equilibrium of \[{{m}_{1}}\] & \[{{m}_{2}}\] \[{{T}_{2}}=({{m}_{1}}+{{m}_{2}}).a\] or, \[{{T}_{2}}=\frac{({{m}_{1}}+{{m}_{2}}){{T}_{3}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\] Given \[{{m}_{1}}=10kg,\]\[{{m}_{2}}=6kg,\]\[{{m}_{3}}=4kg,\] \[{{T}_{3}}=40\,N\] \[\therefore \]\[{{T}_{2}}=\frac{(10+6).40}{10+6+4}=32N\]


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