A) 8.32 kJ
B) 12.36 kJ
C) 16.25 kJ
D) 20.74 kJ
Correct Answer: C
Solution :
[c] \[{{C}_{6}}{{H}_{6}}+\frac{15}{2}{{O}_{2}}\xrightarrow{{}}6C{{O}_{2}}+3{{H}_{2}}O\] 1 mole = 3250 kJ \[\frac{0.39}{78}mole\equiv 3250\times \frac{0.39}{78}=16.25\,\,kJ\]You need to login to perform this action.
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