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NEET Sample Paper NEET Sample Test Paper-88

  • question_answer
    For the cell \[Zn|Z{{n}^{2+}}(1M)\parallel C{{u}^{2+}}(1M)|Cu,\]\[E_{cell}^{{}^\circ }\,is\,1.10\,V,\] \[E_{C{{u}^{2+}}/Cu}^{{}^\circ }=0.34\,V\] and for the cell \[Cu|C{{u}^{2+}}(1M)\parallel A{{g}^{+}}(1M)|Ag,\] \[E_{cell}^{{}^\circ }=0.46\,V\] hence, \[E_{cell}^{{}^\circ }\] of the cell \[Zn|Z{{n}^{2+}}(1M)\parallel A{{g}^{+}}(1M)|Ag\] is

    A) \[-0.04\,V\]        

    B)        \[+0.04\,V\]

    C) \[+0.30\,V\]      

    D)        \[+1.56\,V\]

    Correct Answer: D

    Solution :

    [d] \[E_{cell}^{0}=E_{Zn/Z{{n}^{2+}}}^{0}+E_{C{{u}^{2+}}/Cu}^{0}\,\,first\,cell\] \[1.10=E_{Zn/Z{{n}^{2+}}}^{0}+0.34\] \[E_{Zn/Z{{n}^{2+}}}^{0}=0.76\,\,V\] \[E_{cell}^{0}=E_{Cu/C{{u}^{2+}}}^{0}+E_{A{{g}^{+}}/Ag}^{0}\,\,\text{second}\,\,cell\] \[0.46=-0.34+E_{A{{g}^{+}}/Ag}^{0}\] \[E_{A{{g}^{+}}/Ag}^{0}=0.80\,\,V\] For third cell \[E_{cell}^{0}=E_{Zn/Z{{n}^{2+}}}^{0}+E_{A{{g}^{+}}/Ag}^{0}\]        \[=0.76+0.80\]        \[=+1.56\,\,V\]


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