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NEET Sample Paper NEET Sample Test Paper-88

  • question_answer
    A projectile is projected at an angle of \[45{}^\circ \] with speed u. The radius of curvature of its trajectory at the maximum height is

    A) \[\frac{{{u}^{2}}}{g}\]                       

    B)        \[\frac{{{u}^{2}}}{4g}\]

    C) \[\frac{2{{u}^{2}}}{g}\]                     

    D)        \[\frac{{{u}^{2}}}{2g}\]

    Correct Answer: D

    Solution :

    [d] At maximum height, \[v=u\,\cos \,45{}^\circ =\frac{u}{\sqrt{2}};\] \[{{a}_{c}}=g\] \[r=\frac{{{\left( \frac{u}{\sqrt{2}} \right)}^{2}}}{g}=\frac{{{u}^{2}}}{2g}\]


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