A) zero
B) one
C) three
D) four
Correct Answer: A
Solution :
[a] \[Ni{{(CO)}_{4}}.\] The O. S. of Ni is zero. Electronic configuration is [Ar] \[3{{d}^{8}}\,4{{s}^{2}}\,4{{p}^{0}}.\] In presence of strong ligand CO the paring of electrons take place and electronic configuration will be [Ar] \[3{{d}^{10}}\,4{{s}^{0}}\,4{{p}^{0}}.\] Hence unpaired electrons is zero.
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