A) \[C{{H}_{2}}=CH-CH=C{{H}_{2}}\]
B) \[C{{H}_{2}}=C=CHC{{H}_{3}}\]
C) \[C{{H}_{3}}C=CC{{H}_{3}}\]
D) All the three
Correct Answer: D
Solution :
[d] Formation of only \[C{{H}_{3}}COOH\]by ozonolysis indicates that the compound Y should be\[C{{H}_{3}}CH=CHC{{H}_{3}}\]which can be formed by all of the three given compounds \[C{{H}_{2}}=CH\underset{X}{\mathop{-}}\,CH=C{{H}_{2}}\xrightarrow{1{{H}_{2}}/Pt}\] \[C{{H}_{3}}-\underset{Y}{\mathop{CH}}\,=CH-C{{H}_{3}}\] \[C{{H}_{3}}C\underset{X}{\mathop{\equiv }}\,CC{{H}_{3}}\xrightarrow{1{{H}_{2}}/Pt}C{{H}_{3}}CH\underset{Y}{\mathop{=}}\,CHC{{H}_{3}}\] \[pH=\frac{1}{2}[p{{K}_{a}}-\log 1]=\frac{p{{K}_{a}}}{2}\]
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