A) \[{{H}_{2}}O,\]\[{{H}_{2}}S{{O}_{4}}\]
B) aqueous \[KOH\]
C) \[MgS{{O}_{4}},\]\[NaB{{H}_{4}}/{{H}_{2}}O\]
D) \[{{B}_{2}}{{H}_{6}},\]\[{{H}_{2}}{{O}_{2}},\]\[O{{H}^{-}}\]
Correct Answer: D
Solution :
[d] We know that \[6C\underset{\text{1-Propene}}{\mathop{{{H}_{3}}-CH}}\,=C{{H}_{2}}\xrightarrow[ether,\,\,0{}^\circ C]{{{B}_{2}}{{H}_{6}}}\] \[2{{(C{{H}_{3}}C{{H}_{2}}C{{H}_{2}})}_{3}}B\xrightarrow[O{{H}^{-}}]{{{H}_{2}}{{O}_{2}}}\] \[6C{{H}_{3}}C{{H}_{2}}\underset{\text{Propanol}}{\mathop{C{{H}_{2}}OH}}\,+2{{H}_{3}}B{{O}_{3}}\]
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